(63n^3-42n^-6)/7n^-2

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Solution for (63n^3-42n^-6)/7n^-2 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

n^-2*((63*n^3-(42*n^-6))/7) = 0

n^-2*((63*n^3-42*n^-6)/7) = 0

(n^-2*(63*n^3-42*n^-6))/7 = 0

63*n^3-42*n^-6 = 0

21*n^3*(3-2*n^-9) = 0

-2*n^-9 = -3 // : -2

n^-9 = 3/2

-9 < 0

1/(n^9) = 3/2 // * n^9

1 = 3/2*n^9 // : 3/2

2/3 = n^9

n^9 = 2/3 // ^ 1/9

n = (2/3)^(1/9)

21*n^3*(n-(2/3)^(1/9)) = 0

(21*n^-2*n^3*(n-(2/3)^(1/9)))/7 = 0

( 21*n^3 )

21*n^3 = 0 // : 21

n^3 = 0

n = 0

( n-(2/3)^(1/9) )

n-(2/3)^(1/9) = 0 // + (2/3)^(1/9)

n = (2/3)^(1/9)

( n^-2 )

1*n^-2 = 0 // : 1

n^-2 = 0

n naleu017Cy do O

n in { 0} 

n = (2/3)^(1/9)

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